The Formula For The Perfect Pint

math
I can only assume that the UK pub chain Taylor Walker is, in the appropriate British parlance, taking the piss, with their commissioning of Mindlab to discover the formula for “the perfect pint.” Though there is a Mind Lab at the University of Sussex, this bit of news is not listed in their news or press section. At any rate, they claim to have “used complex mathematical modelling techniques to discover what conditions are required to enjoy the perfect pint.”
e-pint

So what is the formula for a perfect pint?

Here goes: E = -(0.62T2 + 39.2W2 + 62.4P2) + (21.8T + 184.4W + 395.4P + 94.5M – 90.25V) + 50(S + F + 6.4)

  • E is a factor describing overall enjoyment.
  • T is the ambient temperature in degrees Celsius.
  • W is the number of days until you are required back at work.
  • P is the number of people with whom you are drinking.
  • M is related to your mood whilst drinking the pint.
  • V is related to the volume of the music being played.
  • S and F are related to the availability of snacks and food.

Without the number variants, so slightly simpler, it’s E = -(T2+W2+P2) + (T+W+P+M-V) + 50(S+F+6.4), though it’s hardly E = MC2. Below a presumed “scientist” — he is after all, wearing a lab coat and surrounded by books and beakers — explains it all:

Comments

  1. says

    Jay, could you edit the equation to more clearly indicate the T, W and P are squared to more accurately reflect what is shown in the video. I noticed The Drinks Business did this too, so I figure you were just going off of them. Your simplified breakdown already seemingly indicates some confusion. Albeit it’s mostly for entertainment, but might as well avoid any potential confusion from the start–particularly for those of us geeky enough to actually try this out; )

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